# Solving Complex Algebraic Equations (Solve for x)

In this video, we will be learning how to solve for x (or another variable) in complex algebraic equations using inverse operations.

For Example:

$5(x+4) +2 = 27$

$5(x+4) +2 -2 = 27 -2 \leftarrow$ Subtract 2 from both sides

$\frac {5(x+4)}{5} = \frac{25}{5} \leftarrow$ Divide by 5 on both sides

$(x+4) -4 =5 -4\leftarrow$ Subtract 4 on both sides

$x=1$

Another way of doing this problem:

$5(x+4) +2 = 27 \leftarrow$ Distribute the 5 to the x and the 4

$5x+20 +2 = 27 \leftarrow$ Simplify using addition

$5x+22 -22 = 27 -22 \leftarrow$ Subtract 22 from both sides

$\frac{5x}{5}=\frac{5}{5} \leftarrow$Divide by 5 on each side

$x=1$
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Used by students across the country. Pre-Algebra, Algebra I, Geometry, & Algebra II