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Solving Complex Algebraic Equations (Solve for x)

In this video, we will be learning how to solve for x (or another variable) in complex algebraic equations using inverse operations.

For Example:

 5(x+4) +2 = 27

 5(x+4) +2 -2 = 27 -2 \leftarrow Subtract 2 from both sides

 \frac {5(x+4)}{5} = \frac{25}{5} \leftarrow Divide by 5 on both sides

 (x+4) -4 =5 -4\leftarrow Subtract 4 on both sides

 x=1

 

Another way of doing this problem:

 5(x+4) +2 = 27 \leftarrow Distribute the 5 to the x and the 4

 5x+20 +2 = 27 \leftarrow Simplify using addition

 5x+22 -22 = 27 -22 \leftarrow Subtract 22 from both sides

 \frac{5x}{5}=\frac{5}{5} \leftarrow Divide by 5 on each side

 x=1
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