# Mean

We will start the discussion about the measures of central tendency and dispersion by solving the mean.

In this video, we are going to look at how to solve for the mean. The mean is found by adding up all of the numbers in a set and then dividing it by the total amount of numbers.

• Only $19.95/mo. No commitment. Cancel anytime. For example: With the set {2, 2, 4, 6, 8, 9, 11, 13}, first, add up all the numbers, And then divide it by the amount of numbers, 8. So: $2+2+4+6+8+9+11+13=55$ $55\div8=6.875$ ## Video-Lesson Transcript The mean of a set of numbers is found by adding up all the numbers or the sum of the numbers and dividing it by the amount of numbers. $\dfrac{sum of \#s}{amount of \#s}$ For example: $2, 2, 4, 6, 8, 9, 11, 13$ To find the mean, we would add these all up. $\dfrac{2 + 2 + 4 + 6 + 8 + 9 + 11 + 13}{8}$ $= \dfrac{55}{8}$ $= 6.875$ To find the mean, just add up all the numbers and then divide it by how many numbers there are. # Median In this video, we are going to look at how to solve for the median. The median is the middle number when the numbers are arranged in numerical order. • Only$19.95/mo. No commitment. Cancel anytime.

For example:
With the set {2, 2, 4, 6, 8, 9, 11, 13, 17}, start crossing off numbers from each side, one by one, until you are left with just the middle number. In this set of numbers, 8 is the median.
In cases like {2, 2, 4, 6, 8, 9, 11, 13}, do the same thing by crossing off numbers from each side, one by one, until you are left with the middle number. In this case, however, we are stuck with two numbers in the middle, 6 and 8. Here, the median would be the number in between these two. The way to find that is to solve for the average of the two remaining numbers. So:
$\frac{6+8}{2}=\frac{14}{2}=7$
In this set of numbers, the median is 7.

## Video-Lesson Transcript

The median is the middle number when numbers are arranged in order, numerically.

Put the numbers numerically from smallest to largest.

For example:

$2, 2, 4, 6, 8, 9, 11, 13, 17$

We’ll just look for the middle number by crossing one number from each side.

Now, $8$ is the middle number.

That’s four numbers to the left and four numbers to the right.

$median = 8$

This works if there’s an odd number of values. Because there will be a middle number. Since there is the same amount of numbers on the left and the right.

Let’s see what happens if we have an even number of values.

$2, 2, 4, 6, 8, 9, 11, 13, 17$

Let’s do the same method that we did earlier. Cross out one number from the opposite sides.

We already crossed out three numbers from both sides but we’re left with two numbers which are $6, 8$.

In this case, the median is the number between these two.

The number between $6$ and $8$ is $7$.

So, the median is $7$.

But sometimes we have numbers that are more spaced apart or some decimals that are confusing.

In reality, the median is the average of two numbers that we’re left with.

$\dfrac{6 + 8}{2}$
$= \dfrac{14}{2}$
$= 7$

For this set of numbers,

$median = 7$

It’s very important to have the numbers in order then the median is the middle number.

If there’s an odd number of values, the median is one of the numbers.

If there’s an even number value, the median is the average of the two middle numbers.

# Mode

In this video, we are going to look at how to solve for the mode. The mode is the number that appears most often.

• Only $19.95/mo. No commitment. Cancel anytime. For example: With the set {2, 2, 4, 6, 8, 9, 11, 13}, the mode would be 2 because 2 appears twice while all other numbers appear only once. Remember that the MODE is the number that appears the MOST. ## Video-Lesson Transcript The mode is simply the number that appears most often. If we have $2, 2, 4, 6, 8, 9, 11, 13$ the mode is just $2$. $2$ appeared twice. All the other numbers appeared only once. It appeared most often than the others. So, the mode is $2$. Remember, the mode is most. # Range In this video, we are going to look at how to solve the range. The range is the largest number minus the smallest number. • Only$19.95/mo. No commitment. Cancel anytime.

For example:
With the set {2, 2, 4, 6, 8, 9, 11, 13}, the range would simply be 11 because 13-2=11. This set of numbers spans 11 integers.

## Video-Lesson Transcript

The range of a set of numbers is simply the largest number minus the smallest number.

$largest \# - smallest \#$

Let’s have

$2, 2, 4, 6, 8, 9, 11, 13$

The range is the largest number minus the smallest number.

So range is:

$13 - 2 = 11$

A set of numbers spans $11$ integers.

It goes from $11$ up to $13$.

# Calculate the Mean from a Frequency Table

In this video, we are going to look at how to calculate the mean from a frequency table.

• Only $19.95/mo. No commitment. Cancel anytime. For example: We can translate the table given in the video into a set of numbers. Since 1 student was absent once, we write 1 once. Since 1 student was absent twice, we write 2 once. Since 3 students were absent three times, we write 3 three times. And so on. This gives us a number set of {1, 2, 3, 3, 3, 4, 4, 5, 5, 6}. From here, we can solve for mean as usual. Add up the values, and then divide by the total amount of students. So: $1+2+3+3+3+4+4+5+5+6=36$ $36\div10=3.6$ The mean in this number set is 3.6. ## Video-Lesson Transcript Let’s go over finding the mean if we’re given a table of values. We’re given a table that shows different absences and how many students had each number of absences. Using the table, we need to find the mean of the number of absences. What we can do is write this all out $1, 2, 3, 3, 3, 4, 4, 5, 5, 6$ Now, we can add this all up then divide by the number of students. $\dfrac{1 + 2 + 3 + 3 + 3 + 4 + 4 + 5 + 5 + 6}{10}$ But, there is a proven easier way. Maybe we have a hundred more students. Numbers can get really big. And we don’t want to write a hundred set of numbers. Instead, what we’re going to do find a total. Make a new column on the total number of absences on each one. Now that we have a new column, we can find the sum of these. This is the same as when we add them all up individually. $1 + 2 + 9 + 8 + 10 + 6$ $= 36$ And then let’s divide this by the number of students which is $10$. $mean = \dfrac{36}{10}$ $mean = 3.6$ Again, we can figure out the mean by listing each of the absences and how many times they showed up. Adding them up then dividing by the numbers of students. Or we can just find the total of each row of the table. Add those up but still divide by the number of students. # Calculate the Median from a Frequency Table In this video, we are going to look at how to calculate the median from a frequency table. • Only$19.95/mo. No commitment. Cancel anytime.

For example:
We can translate the table given in the video into a set of numbers. Since 1 student was absent once, we write 1 once. Since 1 student was absent twice, we write 2 once. Since 3 students were absent three times, we write 3 three times. And so on. This gives us a number set of {1, 2, 3, 3, 3, 4, 4, 5, 5, 6}. From here, we can solve for median as usual. Cross off numbers from each side, one by one, until you are left with just the middle number. In this set, we are left with 3 and 4 being in the middle. That means that we have to find the average of these two numbers. So:
$\frac{3+4}{2}=3.5$
In this set of numbers, the median is 3.5.

## Video-Lesson Transcript

In this lesson, we’ll go over finding the median if we’re given a table of data.

We have a table showing absences and the number of students had each number of absences.

We can solve for median by writing the data down.

$1, 2, 3, 3, 3, 4, 4, 5, 5, 6$

We can cross out a number on opposite sides.

And we’re left with two middle numbers:

$3, 4$

We have an even number of values.

Median is the average of two middle numbers.

$\dfrac{3 + 4}{2}$
$median = 3.5$

It’s the number in between $3$ and $4$.

That’s one way to find the answer.

Let’s make a side note and expand on the concept before we make a table.

Here, we have ten numbers.

$\dfrac{10 + 1}{2}$
$= 5.5$

This means that the median is the five-point fifth number.

Which means it’s between the fifth and sixth number.

So we have to find the middle of the fifth and sixth number in the list.

Let’s say we have four numbers.

$1, 2, 5, 7$

So we’ll have

$\dfrac{4 + 1}{2}$
$= 2.5$

The median is the two point fifth number.

So, we have to get the average of the second and third number.

Let’s say we have

$1, 2, 3, 7, 13$

Now, we have five numbers.

If we do the same as above, this will happen

$\dfrac{5 + 1}{2}$

The median is going to equal this:

$= 3$

This is the third number.

One more example.

$1, 2, 7, 12, 13, 15, 40$
$\dfrac{7 + 1}{2}$
$median = 4$

Median is the fourth number from the list.

If we want to know what the median in order, we just have to add one to the total the number of values in the list then divide by two.

Let’s go back to the table.

There were ten students.

The median is the five-point fifth number.

In order, we have to find out what is between the fifth and sixth number.

The fifth number in the list is $3$ and the sixth number is $4$.

We just have to find the average of these two.

$median = \dfrac{3 + 4}{2}$
$median = \dfrac{7}{2}$
$median = 3.5$

This method will help us the most when there are many numbers on the list.

Let’s say we have two hundred numbers and we need to find the median.

So, all we have to do is

$\dfrac{200 + 1}{2}$
$100.5$

So, our median is the number between the one hundredth and one hundred and oneth number.

We don’t need to write all the numbers and cross out from opposite directions until we come up with the middle number on the list.

# Calculate the Mode from a Frequency Table

In this video, we are going to look at how to calculate the mode from a frequency table.

• Only $19.95/mo. No commitment. Cancel anytime. For example: In this table, 3 absences appear 3 times. That is more than any other number of absences in the table. By simply analyzing the table, we can determine that the mode is 3. ## Video-Lesson Transcript Let’s go over finding the mode when we’re given a table. Here, we have a table showing absences and how many students had each of those quantities of absences. To find a mode is probably the easiest to do from a table because the quantities are already here. For each of the absences, we can see how many times it showed up. Well, $3$ absences showed three times. That’s more than any absence. So, the mode is $3$. If we want to write it down, it will look like this: $1, 2, 3, 3, 3, 4, 4, 5, 5, 6$ Here, we can see that $3$ showed up the most because it showed up three times. So, $3$ is the mode. # Calculate the Range from a Frequency Table In this video, we are going to look at how to calculate the range from a frequency table. • Only$19.95/mo. No commitment. Cancel anytime.

For example:
To find the range of absences, just simply subtract the largest number minus the smallest number. Based on this table, we can clearly see that the largest number of absences is 6 and the smallest number of absences is 1. Therefore, 6-1=5. The range is 5.

## Video-Lesson Transcript

We’ll look at finding the range if we’re given a table.

Here, we have a table showing absences and how many students had each of those quantities of absences.

To find the range, we just have to look for the largest number minus the smallest number.

$6 - 1 = 5$
$Range = 5$