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(Unlimited Practice) SAT Math: Solving for a Variable in Terms of Another

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Solve for $x$ in the equation below.

$o=\dfrac{qrs}{p^2}x$

$x=\dfrac{qrs}{p}\sqrt{o}$

$x=\dfrac{\sqrt{qrs}}{p}o$

$x=\dfrac{p^2}{qrs}o$

$x=\dfrac{\sqrt{p}}{qrs}o$

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Solve for $b$ in the equation below.

$2ab=4b+xy$

$4b+xy-2a$

$\dfrac{4b+xy}{2a}$

$\dfrac{xy}{2a-4}$

$\sqrt{\dfrac{xy}{42a}}$

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Solve for $b$ in the equation below.

$n=\dfrac{pqr}{o^2}b$

$b=\dfrac{on}{\sqrt{pqr}}$

$b=\dfrac{\sqrt{pqr}}{o}n$

$b=\dfrac{o^2}{pqr}n$

$b=\dfrac{pqr}{o^2}n$

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Solve for $p$ in the equation below.

$r=\dfrac{tuv}{s^2}p$

$p=\dfrac{tuv}{s^2}r$

$p=\dfrac{s^2}{tuv}r$

$p=\dfrac{tuv}{s}\sqrt{r}$

$p=\dfrac{sr}{\sqrt{tuv}}$

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Solve for $c$ in the equation below.

$w = c - abd$

$c = abd+w$

$c = w + abd$

$c = \dfrac{w}{b}+ad$

$c = \dfrac{w}{ad}+b$

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Solve for $a$ in the equation below.

$d=\dfrac{fgh}{e^2}a$

$a=\dfrac{e^2}{fgh}d$

$a=\dfrac{\sqrt{fgh}}{e}d$

$a=\dfrac{ed}{\sqrt{fgh}}$

$a=\dfrac{fgh}{e^2}d$

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